Question

Calculate the following for the combustion of 1.00 mole of C6H6(L) at 25 degrees celcius, delta Hf, C6H6 (L) = 49.04 kJ/mol.

a) The heat flow at a constant pressure of 1.00 atm.

b) The heat flow at a constant volume

c) The work at a constant pressure of 1.00 atm

d) The work at a constant volume

Answer 1

d) work = -p∆V

At constant volume, ∆V = 0. Hence work done at constant volume = 0.