Calculate the following for the combustion of 1.00 mole of C6H6(L) at 25 degrees celcius, delta Hf, C6H6 (L) = 49.04 kJ/mol.
a) The heat flow at a constant pressure of 1.00 atm.
b) The heat flow at a constant volume
c) The work at a constant pressure of 1.00 atm
d) The work at a constant volume
d) work = -p∆V
At constant volume, ∆V = 0. Hence work done at constant volume = 0.
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