Question

Establish a relation between K and Kc for the reaction

3N2(g) + H2(g) ----> 2NH3(g)

Answer 1

Answer – We are given, reaction –

N₂(g) + 3H₂(g) ----> 2NH₃(g)

We know the Kp is the equilibrium constant for partial pressure of the gases and Kc for the concentration.

We know the Kp and Kc expression for this given reaction as follow –

Kc = [NH₃(g)]² / [N₂(g)][H₂(g)]³

Kp = P(NH₃(g))²/ P(N₂(g)) (H₂(g))³

We know the relation between the Kp and Ka and it is as follow –

Kp = Kc.(RT)^∆n

We know ∆n is the change in moles of reaction

∆n = Sum of the moles of product – Sum of the moles of the reactant

      = 2 – 4

   = -2

So, a relation between Kp and Kc for the given reaction is -

Kp = Kc.(RT)^-2