Half reaction of SnCl4 + Zn -> Sn + ZnCl2
For half reactions, note that we must first identify which species is reducing/oxidizing
so
SnCl4 --> Sn
Zn --> ZnCl2
note that Cl is actually Cl- and is spectator ion
so
Sn+4(aq) --> Sn(s)
balance electrons
Sn+4(aq) + 4e- --> Sn(s)
for
Zn(s) --> Zn+2(aq)
balance e-
Zn(s) --> Zn+2(aq)+ 2e-
Note that Zinc is oxidizing and Sn is reducing;
Sn+4(aq) + 4e- --> Sn(s)
Zn(s) --> Zn+2(aq)+ 2e-
The balance:
Sn+4(aq) + 4e- --> Sn(s)
2Zn(s) --> 2Zn+2(aq)+ 4e-
Overall reaction
Sn+4(aq) + 2Zn(s) --> 2Zn+2(aq) + Sn(s)
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