Question

How many grams of Fe(CH3COO)3 are there in 202 grams of an aqueous solution that is...

How many grams of Fe(CH3COO)3 are there in 202 grams of an aqueous solution that is 11.6% by weight Fe(CH3COO)3? __ g Fe(CH3COO)3

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Answer #1

Given that

% by weight Fe(CH3COO)3 = 11.6

weight of the Fe(CH3COO)3 solution = 202 g

weight of the Fe(CH3COO)3 = ?

We know that

(w/w) % = ( weight of the solute / weight of the solution) x 100

Then,

% weight of Fe(CH3COO)3 = [weight of the Fe(CH3COO)3/ weight of the Fe(CH3COO)3 solution] x 100

11.6 = [weight of Fe(CH3COO)3 / 202 g] x 100

weight of Fe(CH3COO)3 = 11.6 x 202 / 100 = 23.432 g

Therefore,

weight of Fe(CH3COO)3 = 23.432 g

Hence,

23.432 grams of Fe(CH3COO)3 are there in 202 grams of an aqueous solution that is 11.6% by weight Fe(CH3COO)3.

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