Question

If 5.31 g of CuNO3 is dissolved in water to make a 0.210 M solution, what is the volume of the solution?

Answer 1

Molar mass of CuNO3 = 1*MM(Cu) + 1*MM(N) + 3*MM(O)

= 1*63.55 + 1*14.01 + 3*16.0

= 125.56 g/mol

mass of CuNO3 = 5.31 g

we have below equation to be used:

number of mol of CuNO3,

n = mass of CuNO3/molar mass of CuNO3

=(5.31 g)/(125.56 g/mol)

= 4.229*10^-2 mol

we have below equation to be used:

M = number of mol / volume in L

0.21 = 4.229*10^-2/ volume in L

volume = 0.201384 L

volume = 201 mL

Answer: 201 mL