Question

If 5.00 g of NaCl react with 5.00 g AgNO3, Which is the limiting reactant? Show your calculations.

Answer 1

Molar mass of NaCl = 1*MM(Na) + 1*MM(Cl)

= 1*22.99 + 1*35.45

= 58.44 g/mol

mass of NaCl = 5.0 g

we have below equation to be used:

number of mol of NaCl,

n = mass of NaCl/molar mass of NaCl

=(5.0 g)/(58.44 g/mol)

= 8.556*10^-2 mol

Molar mass of AgNO3 = 1*MM(Ag) + 1*MM(N) + 3*MM(O)

= 1*107.9 + 1*14.01 + 3*16.0

= 169.91 g/mol

mass of AgNO3 = 5.0 g

we have below equation to be used:

number of mol of AgNO3,

n = mass of AgNO3/molar mass of AgNO3

=(5.0 g)/(169.91 g/mol)

= 2.943*10^-2 mol

we have the Balanced chemical equation as:

NaCl + AgNO3 ---> AgCl + NaNO3

1 mol of NaCl reacts with 1 mol of AgNO3

for 0.0856 mol of NaCl, 0.0856 mol of AgNO3 is required

But we have 0.0294 mol of AgNO3

so, AgNO3 is limiting reagent

Answer: AgNO3