Question

If 2.00g of p-Aminophenol ( 109.1 g/mol) reacts with 5.00 mL of acetic anhydride (102.1 g/mol and density = 1.08 g/mL), what mass of acetaminophen (180.2 g/mol) would be made? Show all calculations.

Mass of acetaminophen: _________________

b. If you only isolated 2.41 g of acetaminophen, what would the percent yield of your reaction be? Show all calculations.

Percent Yield: _________________

Answer 1

p-Aminophenol + acetic anhydride -----> acetaminophen + acetic acid

1 eq of p-Aminophenol reacts with 1 eq of acetic anhydride to produce 1 eq of acetaminophen.

p-Aminophenol = 2.00 g / 109.1 g/mol => 0.01833 moles

acetic anhydride = 5.0 mL * 1.08 g/mL / 102.1 g/mol => 0.05288 moles

So p-Aminophenol is limiting reagent

Mass of acetaminophen = 0.01833 moles * 180.2 g/mol => 3.30 g

b) % Yield = (mass of actual product /mass of expected product ) * 100

% Yield = (2.41 g / 3.30 g) * 100

% Yield = 73 %