Question

NH3(g) + O2(g) --> NO2(g) + H2O(g) Consider the above unbalanced equation. What volume of NH3 at 870 mm Hg and 17.3°C is needed to react with 180 mL of O2 at 724 mm Hg and 21.8°C? Please provide the answer in mL

Answer #1

4 NH3 + 7 O2 ---> 4 NO2 + 6 H2O

step 1: calculate mol of O2

we have:

P = 724.0 mm Hg

= (724.0/760) atm

= 0.9526 atm

V = 180.0 mL

= (180.0/1000) L

= 0.18 L

T = 21.8 oC

= (21.8+273) K

= 294.8 K

find number of moles using:

P * V = n*R*T

0.9526 atm * 0.18 L = n * 0.08206 atm.L/mol.K * 294.8 K

n = 7.085*10^-3 mol

step 2: find mol of NH3

from reaction:

mol of NH3 = (4/7)*moles of O2

= (4/7)*7.085*10^-3 mol

= 4.049*10^-3 mol

step 3: find volume

we have:

P = 870.0 mm Hg

= (870.0/760) atm

= 1.1447 atm

T = 17.3 oC

= (17.3+273) K

= 290.3 K

we have below equation to be used:

P * V = n*R*T

1.1447 atm * V = 4.049*10^-3 mol* 0.0821 atm.L/mol.K * 290.3 K

V = 0.0843 L

V = 84.3 mL

Answer: 84.3 mL

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CO2(g) + H2O(g)
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O2 are required to react with 15.0 g of
C2H6? Use at least as many significant
figures in your molar masses as in the data given
g O2
(b) What mass of CO2 is produced?
g CO2
(c) What mass of H2O is produced?
g H2O

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4 NO2(g) + 6 H2O(g)
--> 7 O2(g) + 4
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In the reaction above, how many grams of NH3 will be
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Show your work.
In the reaction above, given the conditions described in Part E,
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Al2(SO4)3(aq) +
H2(g)
Consider the unbalanced equation above. What volume of 0.465
M H2SO4 is needed to react with
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Al2(SO4)3? Use a molar mass with
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Consider the following reaction:
4 NH3 + 5O2 ->
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How many moles of O2 are needed to react with 4.2 mol
NH3?
How many moles of H2O can be produced from 1.34 mol
O2?
How many grams of NH3 will react with 43.4 g
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What mass of carbon dioxide (CO2) can be produced from 11.2 g of
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When the initial concentration of NO2 is 100 mM, it takes 55 s
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