Question

What is the volume in liters of 80.9 g of CO₂ at 336 mm Hg and 159°C?

Answer 1

Molar mass of CO2 = 1*MM(C) + 2*MM(O)

= 1*12.01 + 2*16.0

= 44.01 g/mol

mass of CO2 = 80.9 g

we have below equation to be used:

number of mol of CO2,

n = mass of CO2/molar mass of CO2

=(80.9 g)/(44.01 g/mol)

= 1.838 mol

we have:

P = 336.0 mm Hg

= (336.0/760) atm

= 0.4421 atm

n = 1.838 mol

T = 159.0 oC

= (159.0+273) K

= 432 K

we have below equation to be used:

P * V = n*R*T

0.4421 atm * V = 1.8382 mol* 0.0821 atm.L/mol.K * 432 K

V = 147 L

Answer: V = 147 L