Question

Calculate the amount of energy produced in a nuclear reaction in which the mass defect is 0.187456 amu.

9.3318 × 10⁻²⁰ J

3.11278 × 10⁻²⁸ J

1.6847 × 10¹⁶ J

2.7976 × 10⁻¹¹ J

Answer 1

Given : Mass Defect =m = 0.187456 amu.

m = 0.187456 x 1.66 x 10^-27 Kg = 3.11 x 10^-28 Kg ---------- (1 amu = 1.66 x 10^-27 Kg)

Speed of light = C = 3 x 10⁸ m/s.

Energy (E) produced corresponding to the mass defect (m) is given by the equation,

E = mC². Mass energy relation

E = (3.11 x 10^-28) x (3 x 10⁸)².

E = 3.11 x 10^-28 x 9 x 10¹⁶.

E = 2.799 x 10^-11 Kg.m/s².

E = 2.799 x 10^-11 J ------(as 1J = 1Kg.1m/1s².)

Answer option : (4) 2.7976 x 10^-11 J

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