When 40.0 g of NaOH is added to water to make 550.0 g of solution, the temperature increases from 22.0 oC to 41.3 oC. What is the heat of solution for sodium hydroxide per mole? Assume the specific heat capacity for the solution is 4.18 J/goC.
mass of solution m = 550g
T1 = 220C
T2 = 41.30C
q = mcT
= 550*4.18*(41.3-22) = -44370J = -44.37KJ
no of moles of NaOH = W/G.M.Wt
= 40/40 =1 moles
Kj concerted to KJ per mole = -44.37KJ/1 mole = -44.37KJ/mole NaOH >>>>>answer
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