Answer :
Chemical formula of nitrogen trifluoride = NF3
Given, mass of NF3 taken = 271.7 g
Volume of vessel = 60 L
Temperature (T) = 48°C = 321 K
( Since , 0°C = 273 K )
R (gas constant) = 0.08206 L atm / ( mol-K)
Molar mass of NF3 = 71 g/mol
Moles of NF3 ( n) = mass of NF3 taken / molar mass
= 271.7 g / 71 g/mol = 3.827 mol
Using ideal gas equation to calculate pressure (P)
PV = nRT
P = nRT / V
= 3.827 * 0.08206 * 321 / 60
= 1.68 atm
Pressure (atm ) = 1.68
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