What is the vacancy concentration of Fe at 850 °C and 1250 °C given the density (7.65g/cm3 ), and activation of energy for vacancy formation (1.08eV/atom).
Determination of the number of vacancies per cubic meter in iron at 850°C (1123 K) and 1250 °C (1523 K ) requires the utilization of following equation:
Nv = N * exp(-Qv/KT) = NA * ρfe / Afe *exp(-Qv/KT)
Nv = number of vacancies per cubic meter
NA = Avogadro's number = 6.022 * 1023 atoms/mol
ρfe = Density of iron = 7.65g/cm3
Afe = Atomic mass of iron = 55.85g/mol
Qv = activation of energy for vacancy formation (1.08eV/atom)
K = Boltzmann constant = 8.62 *10-5 ev/atom.K
At temperature 850°C (1123 K)
Nv = NA * ρfe / Afe *exp(-Qv/KT)
Nv = 6.022 * 1023 atoms/mol *( 7.65g/cm3/55.85g/mol) * exp(-1.08eV/atom/( 8.62 *10-5 ev/atom.K * 1123 K)
Nv = 1.18 *1018 cm-3 or 1.18 *1024 m-3
At temperature 1250°C (1523 K)
Nv = NA * ρfe / Afe *exp(-Qv/KT)
Nv = 6.022 * 1023 atoms/mol *( 7.65g/cm3/55.85g/mol) * exp(-1.08eV/atom/( 8.62 *10-5 ev/atom.K * 1523 K)
Nv = 2.20 *1015 cm-3 or 1.18 *1021 m-3
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