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Balance the following redox reaction in acidic solution. What are the coefficients in front of C2H4O...

Balance the following redox reaction in acidic solution. What are the coefficients in front of C2H4O in the balanced reaction? C2H4O(aq) + NnO4-(aq) → C2H4O2(aq) + MnO2(aq)

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Answer #1


C in C2H4O has oxidation state of -1
C in C2H4O2 has oxidation state of 0
So, C in C2H4O is oxidised to C2H4O2

Mn in MnO4- has oxidation state of +7
Mn in MnO2 has oxidation state of +4
So, Mn in MnO4- is reduced to MnO2





Reduction half cell:
MnO4- + 3e- --> MnO2
Oxidation half cell:
C2H4O --> C2H4O2 + 1e-
Balance number of electrons to be same in both half reactions

Reduction half cell:
MnO4- + 3e- --> MnO2
Oxidation half cell:
3 C2H4O --> 3 C2H4O2 + 3e-

Lets combine both the reactions.
MnO4- + 3 C2H4O --> MnO2 + 3 C2H4O2
Balance Oxygen by adding water

MnO4- + 3 C2H4O + H2O --> MnO2 + 3 C2H4O2

Balance Hydrogen by adding H+
MnO4- + 3 C2H4O + H2O --> MnO2 + 3 C2H4O2 + 2 H+
This is balanced chemical equation in acidic medium

coefficient of C2H4O is 3

Answer: 3

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