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What is the change in the entropy when 1g of benzene, boils reversibly at its boiling...

What is the change in the entropy when 1g of benzene, boils reversibly at its boiling point of 80.1C and a constant pressure of 1atm? The heat of vaporization of benzene is 395 J/g

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Answer #1

Hvap = 395 J / g

mass of benzene = 1 g

heat = Hvap   x mass

          = ( 395 J / g ) x 1g

          = 395 J

Temperature = T = 80.1 + 273 = 353.1 K

change in entropy = heat / temperature

                              = 395 / 353.1

                             = 1.19 J / K

change in entropy = 1.19 J / K

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