Question

Part A A calorimeter contains 35.0 mL of water at 11.0 ∘C . When 1.30 g...

Part A

A calorimeter contains 35.0 mL of water at 11.0 ∘C . When 1.30 g of X (a substance with a molar mass of 46.0 g/mol ) is added, it dissolves via the reaction

X(s)+H2O(l)→X(aq)

and the temperature of the solution increases to 29.0 ∘C .

Calculate the enthalpy change, ΔH, for this reaction per mole of X.

Assume that the specific heat of the resulting solution is equal to that of water [4.18 J/(g⋅∘C)], that density of water is 1.00 g/mL, and that no heat is lost to the calorimeter itself, nor to the surroundings.

Express the change in enthalpy in kilojoules per mole to three significant figures.

Part B

Consider the reaction

C12H22O11(s)+12O2(g)→12CO2(g)+11H2O(l)

in which 10.0 g of sucrose, C12H22O11, was burned in a bomb calorimeter with a heat capacity of 7.50 kJ/∘C. The temperature increase inside the calorimeter was found to be 22.0 ∘C. Calculate the change in internal energy, ΔE, for this reaction per mole of sucrose.

Express the change in internal energy in kilojoules per mole to three significant figures.

Homework Answers

Answer #1

Part A

1.30 g of X (a substance with a molar mass of 46.0 g/mol ) is added.

The number of moles of X added.

The enthalpy change for the reaction

The specific heat of the solution is 4.18 J/ (g deg C)

The enthalpy change for the reaction

This is the enthalpy change for the dissolution of 0.02826 moles of X. For 1 mole of X, the enthalpy change is

Convert the unit from J to kJ

The answer to three significant figures is

Part B

10.0 g of sucrose (molecular weight 342 g/mol)

The heat capacity is 7.50 kJ/ deg C. The temperature increase is 22.0 deg C.

The change in internal energy for 0.02924 moles of sucrose combustion is

The change in internal energy for 1 mole of sucrose combustion is

To three significant figures, the answer is

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