Consider the reaction:
HNO2 (aq) + H2O (l) ⇄
NO2- (aq) + H3O+
(aq)
Which of the following statements will decrease
the amount of work the system could perform?
- Add water to the reaction vessel
- Add solid NaOH to the reaction (assume no volume change)
- Selectively remove NO2- from the
solution
- Boil off water from the container (increasing the concentration
of all species)
- Increase the concentration of the HNO2
Answer : - Boil off water from the container (increasing the concentration of all species)
Explanation :
HNO2 (aq) + H2O (l) ⇄ NO2- (aq) + H3O+ (aq)
1) if water is added , this is pure liquid . so it does not effect the equilibrium
2) if NaOH is added , then it reacts with H3O+ .so concentration of products decreases. so reaction shift to right side.so work increases
3) if NO2- is removed , then also work increases
4) if concentration of HNO2 increases, then reaction shift to right.so work increases
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