Question

A student is asked to standardize a solution of barium hydroxide. He weighs out 0.925 g potassium hydrogen phthalate (KHC8H4O4, treat this as a monoprotic acid). It requires 28.5 mL of barium hydroxide to reach the endpoint.

A. What is the molarity of the barium hydroxide solution? This barium hydroxide solution is then used to titrate an unknown solution of perchloric acid.

B. If 26.0 mL of the barium hydroxide solution is required to neutralize 26.9 mL of perchloric acid, what is the molarity of the perchloric acid solution?

Answer #1

- potassium hydrogen phthalate molecular wieght is 204.22 g/mol
- no. of moles of potassium hydrogen phthalate is 0.925/204.22 = 0.00453 moles
- 2 moles of potassium hydrogen phthalate requires 1 mole of barium hydroxide (since it is diacidic base).
- i.e., 0.00225 moles of barium hydroxide requires to nutralise 0.925 g of potassium hydrogen phthalate
- molarity of Ba(OH)
_{2}is 0.00225/0.0285 = 0.079 M - for neutralization formula is
M
_{1}V_{1}/N_{1 =}M_{2}V_{2}/N_{2} - M
_{1}= 0.079 m, V_{1}=26 mL, N_{1}= 2, V_{2}= 26.9, N_{2}= 1, M_{2}= ? - (0.079 X 26)/2 = (M
_{2}X 26.9)/1 - 1.027 = M
_{2}X 26.9 - M
_{2}= 1.027/26.9 = 0.038 M **molarity of perchloric acid is 0.038**

A student is asked to standardize a solution of
potassium hydroxide. He weighs out
0.950 g potassium hydrogen phthalate
(KHC8H4O4, treat this as a
monoprotic acid).
It requires 31.8 mL of potassium
hydroxide to reach the endpoint.
A. What is the molarity of the potassium
hydroxide solution? M
This potassium hydroxide solution is then used to
titrate an unknown solution of perchloric
acid.
B. If 16.7 mL of the
potassium hydroxide solution is required to
neutralize 27.5 mL of perchloric
acid,...

A student is asked to standardize a solution of calcium
hydroxide. He weighs out 0.925 g potassium hydrogen phthalate
(KHC8H4O4, treat this as a monoprotic acid). It requires 28.3 mL of
calcium hydroxide to reach the endpoint.
A. What is the molarity of the calcium hydroxide solution? This
calcium hydroxide solution is then used to titrate an unknown
solution of hydroiodic acid.
B. If 13.3 mL of the calcium hydroxide solution is required to
neutralize 29.9 mL of hydroiodic acid,...

A student is asked to standardize a solution of calcium
hydroxide. He weighs out 0.988 g potassium hydrogen phthalate
(KHC8H4O4, treat this as a monoprotic acid). It requires 18.7 mL of
calcium hydroxide to reach the endpoint.
A. What is the molarity of the calcium hydroxide solution? This
calcium hydroxide solution is then used to titrate an unknown
solution of hydroiodic acid.
B. If 12.7 mL of the calcium hydroxide solution is required to
neutralize 14.9 mL of hydroiodic acid,...

A student is asked to standardize a solution of calcium
hydroxide. He weighs out 0.905 g potassium hydrogen phthalate
(KHC8H4O4, treat this as a monoprotic acid). It requires 31.0 mL of
calcium hydroxide to reach the endpoint.
A. What is the molarity of the calcium hydroxide solution?
This calcium hydroxide solution is then used to titrate an
unknown solution of hydrochloric acid.
B. If 25.0 mL of the calcium hydroxide solution is required to
neutralize 19.3 mL of hydrochloric acid,...

A student is asked to standardize a solution of calcium
hydroxide. He weighs out 0.921g potassium
hydrogen phthalate (KHC8H4O4,
treat this as a monoprotic acid).
It requires 17.3 mL of calcium
hydroxide to reach the endpoint.
A. What is the molarity of thecalcium
hydroxide solution?
M=?
his calcium hydroxidesolution is then used to
titrate an unknown solution ofhydrobromic
acid.
B. If 19.5 mL of the
calcium hydroxide solution is required to
neutralize 14.2 mL ofhydrobromic
acid, what is the molarity...

1. A student is asked to standardize a solution of
sodium hydroxide. He weighs out
0.939 g potassium hydrogen phthalate
(KHC8H4O4, treat this as a
monoprotic acid).
It requires 27.5 mL of sodium
hydroxide to reach the endpoint.
A. What is the molarity of the sodium
hydroxide solution? ______M
This sodium hydroxide solution is then used to
titrate an unknown solution of hydrobromic
acid.
B. If 14.7 mL of the
sodium hydroxide solution is required to
neutralize 23.4 mL ofhydrobromic...

Potassium hydrogen phthalate is a solid, monoprotic acid
frequently used in the laboratory to standardize strong base
solutions. It has the unwieldy formula of KHC8H4O4. This is often
written in shorthand notation as KHP
1. How many grams of KHP are needed to exactly neutralize 36.8
mL of a 0.337 M sodium hydroxide solution ?
2. What volume of a 0.381 M barium hydroxide solution is needed
to exactly neutralize 5.80 grams of KHP ?
3. If 4.19 grams of...

You are going to standardize your sodium hydroxide by titrating
with potassium hydrogen phthalate. As an example, you dissolve
0.3365 g of potassium hydrogen phthalate, otherwise known as KHP
(KHC8H4O4) in water in a 250.0 mL Erlenmeyer flask and then add
phenolphthalein indicator. You then titrate with your sodium
hydroxide solution, which is in a buret, and you determine that the
equivalence point is at 12.44 mL of your sodium hydroxide solution.
Determine the molarity of your sodium hydroxide solution....

Potassium hydrogen phthalate is a solid, monoprotic acid
frequently used in the laboratory as a primary standard. It has the
unwieldy formula of KHC8H4O4. This is often written in shorthand
notation as KHP. If 30.7 mL of a barium hydroxide solution are
needed to neutralize 1.18 grams of KHP, what is the molarity of the
barium hydroxide solution?

Potassium hydrogen phthalate is a solid, monoprotic acid
frequently used in the laboratory to standardize strong base
solutions. It has the unwieldy formula of KHC8H4O4. This is often
written in shorthand notation as KHP. How many grams of KHP are
needed to exactly neutralize 32.0 mL of a 0.332 M calcium hydroxide
solution ?
What volume of a 0.232 M calcium hydroxide solution is needed to
exactly neutralize 3.54 grams of KHP ?

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 9 minutes ago

asked 15 minutes ago

asked 16 minutes ago

asked 28 minutes ago

asked 56 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago