Question

How many grams of FeCl3·6H2O are needed to provide 10.0 g of H2O?

Answer 1

Here we have the molecule that

So in a molecule of we need 1 mole of and 6 moles of

Now total mass of is equal to

= (mass of + mass of )

= 162.2+108

= 270.2 gm

Now we can say 108 gm of water are needed provide total mass of 270.2 gm of

Then 10  gm of water are needed to provide as

Hence 25 gm of are needed to provide 10 gm of water.