Silver can be plated out of a solution containing Ag+ according to the half-reaction
Ag+(aq)+e−→Ag(s)
How much time (in minutes) does it take to plate 12 g of silver
using a current of 4.4 A ?
40.7 minutes
Explanation
Ag+(aq) + e ------> Ag(s)
To deposite 1mole of Ag ,1 mole of electrons reauired
required mass of Ag = 12g
molar mass of Ag = 107.868g/mol
no of moles of Ag to be deposited = 12g/107.868g/mol = 0.11125mol
no of moles of electrons required = 0.11125mol
Faraday constant = 96485C/mol
No of coloumbs required = 0.11125mol × 96485C/mol = 10734 C
Current = 4.4A
1A = 1Coulombs per second
4.4A = 4.4Coulombs per second
Time required to deposit 12g Ag = 10734C/4.4C/s = 2439.5 s = 40.7minutes
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