Question

Which of the following aqueous solutions would have the highest boiling point? Solve the boiling point for the correct one.

A. .50 M NaSO3

B. 1.0 M NaCI

C. 2.0 M C6H14

D. 1.5 M HCI

E. .5 M (NH4)3 PO4

Answer 1

According to Colligative properties the compound which contains more number particles will show more valu of colligative property.

Assume all are in equal volume solutions

a)

Na2so3 -----> 2Na+ + So3-

Number of moles of particles in given solution = 0.5 * 3 = 1.5 moles

b)

NaCl -------> Na+ Cl-

Number of moles of particles in given solution = 1 * 2 = 2 moles

c)

C6H14 -------> C6H14

Number of moles of particles in given solution = 2 * 1 = moles

d)

HCl -------> H+ + Cl-

Number of moles of particles in given solution = 1.5 *2 = 3 moles

e)

(NH4)3PO4 ------> 3 NH4+ + PO43-

Number of moles of particles in given solution = 4 * 0.5 = 2 moles

Among all options HCl has high number of particles so it has highest boiling point.

Answer: D