Question

A tank contains helium for filling balloons. It holds 8.00 L of He at 46.6 atm and 22.4 °C. What would be the volume of this helium at 2.14 atm and 14.0 °C?

Answer 1

PV = nRT

where:

P is the pressure of the gas = 46.6 atm

V is the volume of the gas = 8 Liter

n is the amount of substance of gas (in moles)

R is gas constant = = 0.0821 L atm K-1 Mol-1

T is the absolute temperature of the gas = 22.4 + 273 = 295.4 K

substitute in the equation and calculate Moles

n = 46.6 x 8 / 0.0821 x 295.4 = 15.37 moles

Using the mole value and above equation we can calcuate Volume of the baloon

P = 2.14 atm V = ?

n = 15.37 moles T = 273 +14 = 287

V = 0.0821 L atm K-1 Mol-1 x 15.37 moles x 287 K / 2.14 atm = 169.25 Liter

Hence Volume of the baloon is 169.25 Liter

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answered by: anonymous