Part C
In Part A, you found the amount of product (1.80 mol P2O5 ) formed from the given amount of phosphorus and excess oxygen. In Part B, you found the amount of product (1.40 mol P2O5 ) formed from the given amount of oxygen and excess phosphorus.
Now, determine how many moles of P2O5 are produced from the given amounts of phosphorus and oxygen.
The reaction product depends on limiting reactant and it stops when the limiting reactant gets over.
and limiting reactant always gives least amount of product(as understood that it will stop the reaction as soon as it is over)
We have 1.8 mol P2O5 mol from certain amount of reactant and 1.4 mol of P2O5 from other
the product obtained is the least amount and will be mainly governed by given amount of oxygen as in that case the product formed is less.
1.4 moles of prodcut is formed
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