Question

A solution is made by dissolving 54.0 g of silver nitrate in enough water to make 350.0 mL. A 10.00 mL portion of this solution is then diluted to a final volume of 250.0 mL. What is the TOTAL concentration of ions present in the final solution?

0.908 M

1.82 M

0.0122 M

0.0726 M

0.0363 M

Answer 1

mass of silver nitrate = 54.0g  

volume of solution = 350mL

Molarity of solution = moles / volume(L)

= (mass/molarmass) (1000/350)

= (54g/170) (1000/350)

= 0.9075 M

NOw 10 mL of this solution is diluted to 250ML

Thus

M1V1 = M2V2

0.9075 x 10 = 250 xM2

the molarity of diluted solution = 0.03630 M

The solution has Ag+ and NO3- ions.

The [Ag+] in solution = 0.03630 M

[NO3-] in solution = 0.03630 M

Thus the total concentration of ions = 0.03630 + 0.03630 M

=0.07260 M

OPtion 4