Question

If 8.95 g of CuNO3 is dissolved in water to make a 0.120 M solution, what is the volume of the solution?

Answer 1

Molarity = number of moles of solute/Volume of the solution(L) ------(1)

Given Molarity = 0.120 M

Amount of solute CuNO3= 8.95 g

Number of moles of CuNO3 = 8.95g /125.54 g/mol (molar mass of CuNO3)

= 0.0716 moles

From equation (1)

0.120 M = 0.0716 moles / Volume of solution in L

Volume of the solution = 0.0716 moles / 0.120 M = 0.596 L = 596 mL

**For reference :

Molecular weight of CuNO3 calculation

Cu = 63.54

N = 14

O = 16

Molecular weight of CuNO3 = 63 + 14+ 3*16 = 125 g/mol