Calculate the [OH−] of each aqueous solution with the following [H3O+].
Part A
coffee, 1.0×10−5 M
Express your answer using two significant figures.
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[OH−] = | M |
Part B
soap, 1.0×10−8 M
Express your answer using two significant figures.
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[OH−] = | M |
Part C
cleanser, 4.9×10−10 M
Express your answer using two significant figures.
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[OH−] = | M |
Part D
lemon juice, 2.5×10−2 M
Express your answer using two significant figures.
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[OH−] = | M |
Sol :-
Ionic product of water (Kw) = [H3O+].[OH-]
Kw of water at 25 0C = 1.0 x 10-14 M2
again,
[H3O+] = Kw/[OH-]
[OH-] = 1.0 x 10-14 M2 / [H3O+]
Part. (A). [H3O+] = 1.0 x 10-5 M
[OH-] = 1.0 x 10-14 M2 / 1.0 x 10-5 M
[OH-] = 1.0 x 10-9 M
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Part. (B). [H3O+] = 1.0 x 10-8 M
[OH-] = 1.0 x 10-14 M2 / 1.0 x 10-8 M
[OH-] = 1.0 x 10-6 M
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Part. (C). [H3O+] = 4.9 x 10-10 M
[OH-] = 1.0 x 10-14 M2 / 4.9 x 10-10 M
[OH-] = 2.0 x 10-5 M
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Part. (D). [H3O+] = 2.5×10−2 M
[OH-] = 1.0 x 10-14 M2 / 2.5×10−2 M
[OH-] = 4.0 x 10-13 M
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