define the standard heat of formation of MgCO3.
Mg(s) + C(graphite) + 3/2O2(g)
MgCO3(s)
This reaction that cannot be carried out directly. So the enthalpy
change for the reaction must be calculated via indirect means.
we got several reaction with each
H to find the
H of MgCO3 formation, these are:
Mg (s) + 2HCl (aq)
MgCl2 (aq) + H2 (g) H
= - 641.8 kJ/mol (1)
MgCO3 (s) + 2HCl (aq) MgCl2 (aq) + H2O (l) + CO2 (g) H = -90kJ /mol (2)
C(s) + O2 (g) CO2 (g) H = -393kJ /mol (3)
H2 (g) + 1/2 O2 (g) H2O (l) H = -285kJ /mol (4)
Reversing equation 2,
MgCl2 (aq) + H2O (l) + CO2 (g) MgCO3 (s) + 2HCl (aq) H = 90kJ /mol (5)
Adding equation (1),(3),(4) & (5) to get the required equation :
Mg(s) + C(s) + 3/2O2(g) MgCO3(s)
H = (- 641.8 kJ/mol) + (-393 kJ /mol) + ( -285kJ /mol ) + (90kJ /mol )
H = - 1229.8 kJ/mol
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