Question

A solution of AgNO3 is electrolyzed by passing 144 A of current for 102 min. What mass of silver plates out? Want to see how it is worked.

Answer 1

the electrolysis expression is:

Ag1+ + 1e- ------> Ag

1 mol of Ag requires 1 mol of electron

1 mol of electron = 96485 C

So,1 mol of Ag requires 96485 C

let us calculate the charge passed:

t = 102.0 min = 102.0*60 s = 6120 s

time, t = 6120s

Q = I*t

= 144A * 6120s

= 881280 C

mol of Ag plated = 881280/96485 = 9.13386 mol

Molar mass of Ag = 107.9 g/mol

mass of Ag = number of mol * molar mass

= 9.13386 * 107.9

= 986 g

Answer: 986 g