Question

Calculate the mass of water produced when 2.63 g of butane reacts with excess oxygen.

Express your answer to three significant figures and include the appropriate units.

Answer 1

2C4H10 + 13O2 ------> 8CO2 + 10H2O

no of moles of butane   = W/G.M.Wt

                                       = 2.63/58 = 0.0453 moles

2 moles of C4H10 react with O2 to gives 10 moles of H2O

0.0453 moles of C4H10 react with O2 to gives = 10*0.0453/2   = 0.2265 moles of H2O

mass of H2O = no of moles * gram molar mass

                        = 0.2265*18   = 4.08g of H2O >>>>answer