Question

Part A

For the reaction

3A(g)+3B(g)⇌C(g)

Kc = 85.2 at a temperature of 41 ∘C .

Calculate the value of Kp.

Express your answer numerically.

Part B

For the reaction

X(g)+3Y(g)⇌3Z(g)

Kp = 1.39×10⁻² at a temperature of 179 ∘C .

Calculate the value of Kc.

Express your answer numerically.

Answer 1

A)

T= 41.0 oC

= (41.0+273) K

= 314 K

delta n = number of gaseous molecule in product - number of gaseous molecule in reactant

delta n = -5

Kp= Kc (RT)^delta n

Kp = 85.2*(0.0821*314.0)^(-5)

Kp = 7.48*10^-6

Answer: 7.48*10^-6

B)

T= 179.0 oC

= (179.0+273) K

= 452 K

delta n = number of gaseous molecule in product - number of gaseous molecule in reactant

delta n = -1

Kp= Kc (RT)^deltan

0.0139 = Kc *(0.0821*452.0)^(-1)

Kc = 0.516

Answer: 0.516