Question

A sample representing 60.0g of iron has an inital temperature of 250 degree celsius and 60.0g of gold that has an inital temperature of 45.0 degree celsius are b rought into contact with one another. Assuming no heat is lost to the surroundings, what will be the temperature when two metals reach thermal equilibrium? The specific heat capacity of iron=0.449J/g/C and gold= 0.128J/G/C

Answer 1

Let us denote gold by symbol 1 and iron by symbol 2

m1 = 60.0 g

T1 = 45.0 oC

C1 = 0.128 J/goC

m2 = 60.0 g

T2 = 250.0 oC

C2 = 0.449 J/goC

T = to be calculated

Let the final temperature be T oC

we have below equation to be used:

heat lost by 2 = heat gained by 1

m2*C2*(T2-T) = m1*C1*(T-T1)

60.0*0.449*(250.0-T) = 60.0*0.128*(T-45.0)

26.94*(250.0-T) = 7.68*(T-45.0)

6735 - 26.94*T = 7.68*T - 345.6

T= 205 oC

Answer: 205 oC