Question

Copper has a specific heat capacity of 0.385 J/g^{o}C.
If 12.8 g of copper initially has a temperature of 35.0
^{o}C and it absorbs 367 J of heat, what will be its new
temperature? please give me the process not just the answer

Answer #1

The relation between heat absorbed, mass of substance, specific heat capacity and temperature change is given by,

q=mcT,

where, q is heat absorbed, m is mass pf the substance, c is
specific heat capacity T
is difference between initial and final temperatures i.e.,
(T_{f} - T_{i})

Given, q is 367 J, m is 12.8 gm, c is 0.385 J/g°C, T_{i}
is 35.0°C, so we have to find T_{f}.

Putting all data in the equation,

367 = 12.8 × 0.385 × (T_{f} - 35)

T_{f} - 35 = 367/4.928 = 74.47

So, T_{f} = 74.47 + 35 = 109.47 °C = 109 °C

The following table lists the specific heat capacities of select
substances: Substance Specific heat capacity [J/(g⋅∘C)] silver
0.235, copper 0.385, iron 0.449, aluminum 0.903, ethanol 2.42,
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If the water absorbs 5.07×105 J of heat in the process, what was
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A 2.24...

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