calculate the pH of a buffer solution prepared with 500 mg/L acetic acid (Ch3COOH; pKa=4.74) and 200 mg/L sodium acetate (NaCH3COO) under the following conditions:
a) initially
b) after 20 mg/L of HCl is added
c) after 20 mg/L of NaOH is added
conc of CH3COOH = 500mg/L
conc of CH3COONa = 200mg/L
PH = Pka + log[CH3COONa]/[CH3COOH]
= 4.74 + log200/500
= 4.74 -0.3979 = 4.3421
b. after addition of 20mg/L of HCl
con of CH3COONa = 200-20 = 180mg/L
conc of CH3COOH = 500+20 = 520mg/L
PH = PKa + log[CH3COONa]/[CH3COOH]
= 4.74 + log180/520
= 4.74-0.4607 = 4.2793
c. after addition of 20mg/L
conc of CH3COONa = 200+20 = 220mg/L
conc of CH3COOH = 500-20 = 480mg/L
PH = Pka + log[CH3COONa]/[CH3COOH]
= 4.74 + log220/480
= 4.74-0.3388 = 4.4012 >>>>answer
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