What mass of Ni2+ is produced in solution by passing a current of 67.0 A for a period of 12.0 h , assuming the cell is 87.0 % efficient?
the electrolysis expression is:
Ni2+ + 2e- ------> Ni
1 mol of Ni requires 2 mol of electron
1 mol of electron = 96485 C
So,1 mol of Ni requires 192970 C
let us calculate the charge passed:
t = 12.0 hr = 12.0*3600 s = 43200 s
time, t = 43200s
Q = I*t
= 67A * 43200s
= 2894400 C
mol of Ni plated = 2894400/192970 = 14.99922 mol
Molar mass of Ni = 58.69 g/mol
mass of Ni = number of mol * molar mass
= 14.99922 * 58.69
= 880.3 g
This is mass formed assuming it is 100 % efficient
Now use:
efficiency = actual mass * 100 / theoretical mass
87.0 = actual mass * 100 / 880.3
actual mass = 766 g
Answer = 766 g
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