Question

How many grams of magnesium hydroxide do you need in an antacid tablet to neutralize 20...

How many grams of magnesium hydroxide do you need in an antacid tablet to neutralize 20 mL of stomach acid? (Stomach acid is 0.1M HCl. There are 3.65 g of HCl in 1 L of stomach acid.) Show your work.

Homework Answers

Answer #1

1 L of acid has 3.65 g HCl

that is

1000 mL of acid has 3.65 g HCl

So,

20 mL will have 3.65*20/1000 = 0.073 g

Molar mass of HCl = 1*MM(H) + 1*MM(Cl)

= 1*1.008 + 1*35.45

= 36.458 g/mol

mass of HCl = 0.073 g

mol of HCl = (mass)/(molar mass)

= 0.073/36.458

= 0.0020023 mol

we have the Balanced chemical equation as:

2HCl Mg(OH)2 —> MgCl2 + 2 H2O

From balanced chemical reaction, we see that

when 2 mol of HCl reacts, 1 mol of Mg(OH)2 is formed

mol of Mg(OH)2 formed = (1/2)* moles of HCl

= (1/2)*0.0020023

= 0.0010012 mol

Molar mass of Mg(OH)2 = 1*MM(Mg) + 2*MM(O) + 2*MM(H)

= 1*24.31 + 2*16.0 + 2*1.008

= 58.326 g/mol

mass of Mg(OH)2 = number of mol * molar mass

= 0.0010012*58.326

= 0.0584 g

Answer: 0.0584 g

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