Question

In the laboratory, a student adds 48.5 mL of water to 13.9 mL of a 0.567 M hydrochloric acid solution. What is the concentration of the diluted solution? Assume the volumes are additive.

Answer #1

use dilution formula

M1*V1 = M2*V2

Here:

M1 is molarity of solution before dilution

M2 is molarity of solution after dilution

V1 is volume of solution before dilution

V2 is volume of solution after dilution

we have:

M1 = 0.567 M

V1 = 13.9 mL

V2 = initial volume + added water

= 13.9 mL + 48.5 mL

= 62.4 mL

we have below equation to be used:

M1*V1 = M2*V2

M2 = (M1*V1)/V2

M2 = (0.567*13.9)/62.4

M2 = 0.126 M

Answer: 0.126 M

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