What is the enthalpy change for the reaction, 2 C3H8 (g) + 7 O2 (g) → 6 CO (g) + 8 H2O (g) ? Given: C3H8 (g) + 5 O2 (g) → 3 CO2 (g) + 4 H2O (g) ΔH = –2219.9 kJ 2 CO (g) + O2 (g) → 2 CO2 (g) ΔH = –566.0 kJ Question 7 options: –6137.8 kJ –2785.9 kJ –2741.8 kJ 1653.9 kJ –1653.9 kJ
Answer:
The Answer to the given question has been calculated to be the following:
Enthalpy change (H ) = - 2741.8 kJ .............................. (Answer ) .....for the given reaction.
Solution:
Following is the Explanation and Calculation for obtaining the above Answer , ...in.....image format...........
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