Question

1. How many moles of [OCl^-]_total are in 11 mL of a 5.5% NaOCl solution (d = 1.1 g/mL at 20 °C)?

0.0078 mol

0.0086 mol

0.35 mol

0.86 mol

2. The net ionic reaction of a 5.5% sodium hypochlorite solution (household bleach) with iodide is shown below. What is the best explanation for the presence of H⁺ as a reagent in this reaction? 2 I^- + ClO^- + 2 H⁺ à I₂ + Cl^- + 2 H₂O

NaOCl dissolved in water partitions into HOCl and OCl^-, and OCl^- is a weak acid.

NaOCl dissolved in water partitions into HOCl and OCl^-, and HOCl is a weak acid.

NaOCl dissolved in water partitions into Na⁺ and OCl^-, and Na⁺ is a weak acid.

NaOCl dissolved in water partitions into Na⁺ and OCl^-, and OCl^- is a weak acid.

Answer 1