Question

what is the concentration of 25g of ALCL3 in 243 mL of water

Answer 1

Molar mass of AlCl3 = 1*MM(Al) + 3*MM(Cl)

= 1*26.98 + 3*35.45

= 133.33 g/mol

mass of AlCl3 = 25 g

we have below equation to be used:

number of mol of AlCl3,

n = mass of AlCl3/molar mass of AlCl3

=(25.0 g)/(133.33 g/mol)

= 0.1875 mol

volume , V = 243 mL

= 0.243 L

we have below equation to be used:

Molarity,

M = number of mol / volume in L

= 0.1875/0.243

= 0.772 M

Answer: 0.772 M