Question

What is the molarity of a 45.00 mL solution of LiOH, if 35.50 mL of 1.88 M oxalic acid was used in titrating the LiOH?

Answer 1

Balanced chemical equation is:
C2H2O4 + 2 LiOH ---> Li2C2O4 + 2 H2O


Here:
M(C2H2O4)=1.88 M
V(C2H2O4)=35.5 mL
V(LiOH)=45.0 mL

According to balanced reaction:
2*number of mol of C2H2O4 =1*number of mol of LiOH
2*M(C2H2O4)*V(C2H2O4) =1*M(LiOH)*V(LiOH)
2*1.88*35.5 = 1*M(LiOH)*45.0
M(LiOH) = 2.97 M

Answer: 2.97 M

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