Question

Given the following reactions and their associated enthalpy changes    CO2 (g) →      C (s) +...

Given the following reactions and their associated enthalpy changes

   CO2 (g) →      C (s) + O2 (g)                          ΔH = 393.5 kJ

C3H8 (g) + 5 O2 (g) →     3 CO2 (g) + 4 H2O (g)   ΔH = -2044 kJ

    H2 (g) + 1/2 O2 (g) →        H2O (g)                     ΔH = -241.8 kJ

calculate the enthalpy change for the following reaction:

4 H2 (g) + 3 C (s)→ C3H8 (g)

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Homework Answers

Answer #1

Apply Hess Law

invert rxn 1, since C(s) is neede din the left side with 3x coefficeint

3C(s) + 3O2 = 3CO2(g) HRxn = -3*(393.5) = -1180.5

invert rxn 2, since we need C3H8 in the right side

3CO2 + 4H2O --> C3H8 + 5O2 H = 2044

get rid of water via --> multiplucaiton of rxn 3 by 4

4H2 + 2O2 = 4H2O H= 4*(-241.8)

add all

4H2 + 2O2 + 3CO2 + 4H2O + 3C(s) + 3O2 = 3CO2(g) + C3H8 + 5O2 + 4H2O HRxn = -1180.5+ 2044 +  4*(-241.8)

get rid of similar species

4H2 + 3C(s) = C3H8 HRxn = -103.7 kJ

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