Question

You have found the following: NH3(aq) + H2O(l) <=> OH-(aq) + NH4+(aq) K = (1.8991x10^-5) OH-(aq)...

You have found the following:

NH3(aq) + H2O(l) <=> OH-(aq) + NH4+(aq) K = (1.8991x10^-5)

OH-(aq) + H+(aq) <=> H2O(l) K = (1.067x10^14)

What is the value of K for the following reaction?

NH3(aq) + H+(aq) <=> NH4+(aq)

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Answer #1

Both the equations are added and the same terms are cancelled. The equilibrium constant for the final reaction is, K = K1×K2 = 2.026 × 10^9. The detailed solution is given below:

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