Question

Consider the neutralization reaction between potassium carbonate, K2CO3, and hydrobromic acid, HBr, forming the salt potassium bromide, KBr, carbon dioxide, CO2, and water, H2O. The balanced chemical equation for the reaction is K2CO3(aq)+2HBr(aq)→2KBr(aq)+CO2(g)+H2O(l) In the reaction, K2CO3, HBr, and KBr are strong electrolytes, so these compounds dissociate completely in water to form their respective ions. The total ionic equation is 2K+(aq) + CO32−(aq) + 2H+(aq) + 2Br−(aq)→2K+(aq) + 2Br−(aq) + CO2(g) + H2O(l) To obtain the net ionic equation, the spectator ions K+ and Br− are removed: CO32−(aq)+2H+(aq)→CO2(g)+H2O(l)                                                                            Part A Given the reactant side of the total ionic equation for the neutralization reaction of ammonium hydroxide (NH4OH) with hydrochloric acid (HCl), write the total ionic equation (also known as the complete ionic equation) by entering both the reactant and the product species, separated by the reaction arrow. NH4+(aq)+OH−(aq)+H+(aq)+Cl−(aq)→ ? Be sure to include the charges on the ionic species and the physical state of all the reactant and product species

Answer 1

NH4+(aq)+OH−(aq)+H+(aq)+Cl−(aq) → NH4Cl(aq) + H2O(l)

Ammonium hydroxide reacts with hydrochloric acid to form ammonium chloride and water

In this reaction, NH4Cl and HCl are strong electrolytes hence they are almost completely ionized as NH4+ and Cl- and H+ ion reacts with OH- ion to form unionized water.

The total net ionic equation may be written as

NH4+(aq)+OH−(aq)+H+(aq)+Cl−(aq) → NH4+(aq) + Cl-(aq) + H2O(l)

Net ionic equation is

H+(aq) + OH-(aq) → H2O(l)