Question

Which correctly matches the oxidation number of the elements in each compound given?

	CsO2: Oxidation number of Cs = +4; Oxidation number of O = -2
	KO2: Oxidation number of K = +2; Oxidation number of O = -1
	Li3N: Oxidation number of Li = +3; Oxidation number of N = -3
	Rb2O2: Oxidation number of Rb = +1; Oxidation number of O = -1
	NaNH2: Oxidation number of Na = +1; Oxidation number of N = +1; Oxidation number of H = -1

Answer 1

for CsO2:

Cs=+4

O=-2

for KO2:

K=+1

O=—1/2

for Li3N:

Li=+1

N=-3

For Rb2O2:

Oxidation number of each element in O-2 is

Rb=+2

O=-2

For NaNH2:

Oxidation number of Na = +1

Oxidation number of H = +1

lets the oxidation number of N be x

we have below equation to be used:

1* oxidation number (Na) + 2* oxidation number (H) + 1* oxidation number (N) = net charge

1*(+1)+2*(+1)+1* x = 0

3 + 1 * x = 0

x = -3

So oxidation number of N = -3

Oxidation number of each element in NaNH2 is

Na=+1

H=+1

N=-3

Answer: CsO2