Which correctly matches the oxidation number of the elements in each compound given?  

for CsO2:
Cs=+4
O=2
for KO2:
K=+1
O=—1/2
for Li3N:
Li=+1
N=3
For Rb2O2:
Oxidation number of each element in O2 is
Rb=+2
O=2
For NaNH2:
Oxidation number of Na = +1
Oxidation number of H = +1
lets the oxidation number of N be x
we have below equation to be used:
1* oxidation number (Na) + 2* oxidation number (H) + 1* oxidation number (N) = net charge
1*(+1)+2*(+1)+1* x = 0
3 + 1 * x = 0
x = 3
So oxidation number of N = 3
Oxidation number of each element in NaNH2 is
Na=+1
H=+1
N=3
Answer: CsO2
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