Question

The balanced reaction for the combustion of ethane is shown in the table below. You allow 2.3 mol of ethane (C2H6) to react with 3.5 mol oxygen (O2). Complete the following ICF table to indicate the amounts of all chemical species for the initial, change, and final conditions.

Drag the appropriate amounts to their respective targets.

Answer 1

Let us consider a reaction,

2C2H6(g) +7O2 ---> 4CO2(g)+6 H2O

Given data ,

Number of moles of ethane = 2.3 mol

Number of moles of O2 = 3.5 mol

From the reaction,

For 1 mole of ethane 3.5 mol of O2 required.

Here limiting reagent is O2

For 3.5 moles of O2 = 3.5 / 2.3 moles of C2H6 required.

= 1.52 moles of C2H6 required.

For 1.52 mole of C2H6 = 2 / 1.52 moles of CO2 produced

= 3 / 1.52 mole H2O produced.

= 1.97 mole

2C2H6(g)	+7O2 ------>	4 CO2 +	6H2O
Initial 2.3	3.5	0	0
Change 1.52	3.5	1.52	1.97
Final 0.78	0	1.52	1.97