Question

The melting point of a pure solid (X) is 1 °C. This chemical is not soluble in water.
If you placed a crystal of this solid into a beaker of water at 2 °C

A) the crystal will float;

B) the crystal will sink;

C) the free energy change for X(s) →X(l) would be
negative;

D) the free energy change for X(s) → X(l) would be positive; E) the free
energy change for X(s) → X(l) would be zero.

Answer 1

The melting point of a pure solid (X) is 1 °C.
This means that the intermolecular forces present are weaker.
Hence, the solid is having low density.
THe density of solid will be lower than the density of water.

This chemical is not soluble in water.
Hence, the dissolution of solid in liquid is non spontaneous.
Non spontaneous processes have positive free energy change.

If you placed a crystal of this solid into a beaker of water at 2 °C
A) the crystal will float;
D) the free energy change for X(s) → X(l) would be positive