Question

What volume of 0.178 M Na3PO4 solution is necessary to completely react with 86.6 mL of 0.121 M CuCl2?

Answer 1

the balanced chemical reaction will be--

2Na3po4(aq) + 3CuCl2(aq) ---> 6NaCl(aq) + Cu3(PO4)2(s)

clearly by seeing any 2 compounds in this reaction we can interchange their respective coefficients and then multiply with their respective moles and then equate the same.....

also , coeeficient of na3po4 is 2 and coefficient of cucl2 is 3 ....so we will multiply 3 with tge moles of na3po4 and 2 with the moles of cucl2...and then equate the thing....

moles of na3po4 = 0.178M(given) * volume of na3po4

moles of cucl2 = 0.121M(given) * 86.6ml(given) = (0.0104 * 1000) mili moles = 0.0104 moles of cucl2.

so equating the things as told earlier---

3 * (0.178*(volume of na3po4)) = 2 * (.0104 moles of cucl2)

so, volume of na3po4 required =( 2*.0104)/(3* 0.178) = 0.0392 Litres of na3po4 required to completely react with 0.86.6ml of .121 M of cucl2...