Question

2KHCO3(s)  →  K2CO3(s) + CO2(g) + H2O(l)

How many moles of potassium carbonate will be produced if 487 g of potassium hydrogen carbonate are heated?

Answer 1

Number of moles of potassium hydrogen carbonate = 487 g / 100.115 g/mol = 4.86 mole

from the balanced equation we can say that

2 mole of potassium hydrogen carbonate produces 1 mole of potassium carbonate so

4.86 mole of potassium hydrogen carbonate will produce

= 4.86 mole of potassium hydrogen carbonate *(1 mole of potassium carbonate  / 2 mole of potassium hydrogen carbonate)

= 2.43 mole of potassium carbonate  

Therefore, the number of moles of potassium carbonate produced would be 2.43