Question

How many moles of Al(OH)3 are made when combined 2 moles of Al2(SO4)3 and 9 moles...

How many moles of Al(OH)3 are made when combined 2 moles of Al2(SO4)3 and 9 moles of NaOH?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Reaction of Al2(SO4)3 solution with NaOH forms a precipitate according to the equation: Al2(SO4)3(aq) + 6...
Reaction of Al2(SO4)3 solution with NaOH forms a precipitate according to the equation: Al2(SO4)3(aq) + 6 NaOH (aq) --> 3 Na2SO4 + 2 Al (OH)3 Addition of more NAOH causes the precipiate to redissolve: Al(OH)3 + NaOH --> NaAl(OH)4(aq) Describing the reaction above on would state: If one adds NaOH dropwise to Al2(SO4)3 solution, first one would see a ______ with the formula ________. If one continues to add NaOH then one will observe a formation of a ________ with...
A mixture contains only NaCl and Al2(SO4)3. A 1.75-g sample of the mixture is dissolved in...
A mixture contains only NaCl and Al2(SO4)3. A 1.75-g sample of the mixture is dissolved in water, and an excess of NaOH is added, producing a precipitate of Al(OH)3. The precipitate is filtered, dried, and weighed. The mass of the precipitate is 0.134 g. What is the mass percent of Al2(SO4)3 in the sample?
5. How many grams of AlCl3 are produced when 0.5 mL of a 2.5 M Al2(SO4)3...
5. How many grams of AlCl3 are produced when 0.5 mL of a 2.5 M Al2(SO4)3 solution are used in the reaction? 6 NaCl + Al2(SO4)3 -----> 3 Na2SO4 + 2 AlCl3
Carry out the calculation: In the reaction: 2 Al(NO3)3 +3 Na2SO4 -------> Al2(SO4)3 + 6 NaNO3...
Carry out the calculation: In the reaction: 2 Al(NO3)3 +3 Na2SO4 -------> Al2(SO4)3 + 6 NaNO3 How many grams of aluminum sulfate will form if we start from 25.0 g aluminum nitrate and 50.0 g sodium sulfate?
Al(s) + H2SO4(aq) --> Al2(SO4)3(aq) + H2(g) Consider the unbalanced equation above. What volume of 0.465...
Al(s) + H2SO4(aq) --> Al2(SO4)3(aq) + H2(g) Consider the unbalanced equation above. What volume of 0.465 M H2SO4 is needed to react with excess aluminum to produce 3.94 g of Al2(SO4)3? Use a molar mass with at least as many significant figures as the data given.
please show work - For the reaction: H2SO4(aq) + Al(OH)3 ↔ H2O + Al(OH)(SO4) ; calculate...
please show work - For the reaction: H2SO4(aq) + Al(OH)3 ↔ H2O + Al(OH)(SO4) ; calculate the equivalent weight of Al(OH)3. A.26 B.39 C.78
When solutions of Al(NO3)3 and NaOH are mixed, Al(OH)3 precipitates as a solid according to the...
When solutions of Al(NO3)3 and NaOH are mixed, Al(OH)3 precipitates as a solid according to the following chemical equation. If 98 mL of 1.77 M Al(NO3)3 is mixed with 321 mL of 1.54 M NaOH: How many grams of Al(OH)3 are precipitated? What is the concentration (molarity) of each of the remaining ions in solution? Assume that the volumes are additive.
How many grams of BaSO4 will produced when 2.1 moles of Cr(SO4)3 react?
How many grams of BaSO4 will produced when 2.1 moles of Cr(SO4)3 react?
1.) A student found that the sulfate ion concentration in a solution of Al2(SO4)3 was 0.34...
1.) A student found that the sulfate ion concentration in a solution of Al2(SO4)3 was 0.34 M. What was the concentration of Al2(SO4)3 in the solution? C(Al2(SO4)3)= 2.) To study the effect of dissolved salt on the rusting of an iron sample, a student prepared a solution of NaCl by dissolving 4.250 g of NaCl in enough water to make 204.2 mL of solution. What is the molarity of this solution? C(NaCl) = 3.) A student found that the sulfate...
How many moles of 3H2SO4 + 2Fe -->Fe2(SO4)3 + 3H2; are required to produce 5 moles...
How many moles of 3H2SO4 + 2Fe -->Fe2(SO4)3 + 3H2; are required to produce 5 moles 0f Fe2(SO4)3
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT