Question

How do i find the moles in Calcium Phosphate?

(Ca_{3}(PO_{4})_{2})

Answer #1

How many grams of phosphorus are in a sample of Ca3(PO4)2 that
contains 74.0 g of calcium?
mass phosphorus = _______g

Elemental phosphorus is produced by the reaction, 2 Ca3(PO4)2 + 6
SiO2 + 10 C → 6 CaSiO3 + 10 CO + P4 Suppose that you have 9.0 moles
of Ca3(PO4)2, 21.0 moles of SiO2, and 49.0 moles of C. (a) Which
reactant is limiting? (b) What are the maximum amounts (in moles)
of CaSiO3, CO, and P4 that can be produced?

2 H3PO4(aq) + 3Ca(OH)2(aq) = Ca3(PO4)2 (s) + 6 H2O(l)
1.
a.Calculate the volume of .0500 M phosporic acid that would be
required to exactly react with 20.0 ml of 0.100 M calcium
Hydroxide
b. What mass of calcium phosphate will precipitate?

A) How many moles of oxygen atoms are in 4.48 moles of magnesium
phosphate: Mg3(PO4)2 (Mw. 262.87
g/mol)?
B) How many moles of hydroxide ion are in 4.58 moles of aluminum
hydroxide: Al(OH)3 (Mw. 78.00 g/mol)?
C) How many iron ions are in 4.5 moles of iron (III) carbonate:
Fe2(CO3)3 (Mw. 291.73 g/mol)?

Solid calcium hudoxide reacts with phosphoric acid according to
the following equation:
3 Ca(OH)2+ 2H3PO4--- Ca3(PO4)2+ 6 H2O
what in volume of 0.0220 M phosphoric acid can be neutralized by
94.651 grams of Calcium hydroxide

Consider the following balanced equation:
2H3PO4(aq) + 3Ca(OH)2(s) → 6H2O(l) +
Ca3(PO4)2(s)
If 13.6 moles of H3PO4(aq) and 35.3 moles of
Ca(OH)2(s) are allowed to react, and the percent yield is
84.5%, how many moles of H2O(l) will actually be
produced?
60.5 moles
87.2 moles
95.2 moles
76.7 moles
34.5 moles

What is the solubility of
Ca3(PO4)2 (s) in mg/L, in
a solution buffered at pH 7.2 using a phosphate buffer such that
TOTPO4 = 10-2M?

The Ksp (solubility product) of
calcium phosphate is 1.2 x 10^-26. Find the solubility in moles per
litre of the following.
(a) Calcium phosphate in water.
(b) Calcium phosphate in 0.010 M CaCl2 solution.
Please show all steps. Thank
you.

solutions containing 400 g CaCl2 and 400 g Na3PO4 are mixed how
much Ca3(PO4)2 can be formed
Given equation
3CaCl2 (aq) + 2 Na3PO4 (aq) --> Ca3 (PO4)2 (s) + 6 NaCl
(aq)

How many grams of Ca3(PO4)2 precipitate can form by reacting
169.1 mL of 1.9 M CaBr2 with an excess amount of Li3PO4, given the
balanced equation:
2 Li3PO4 (aq) + 3 CaBr2 (aq) --> 6 LiBr2 (aq) + Ca3(PO4)2
(s)

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